Base | Representation |
---|---|
bin | 100101001100111100001… |
… | …0101101011101111011111 |
3 | 200002210121212001200202200 |
4 | 1022121320111223233133 |
5 | 1132232441142013401 |
6 | 14512521002222543 |
7 | 1035255436120143 |
oct | 112317025535737 |
9 | 20083555050680 |
10 | 5113030032351 |
11 | 16a147317a83a |
12 | 6a6b334b4a53 |
13 | 2b120625c307 |
14 | 13968714d223 |
15 | 8d005841686 |
hex | 4a67856bbdf |
5113030032351 has 6 divisors (see below), whose sum is σ = 7385487824520. Its totient is φ = 3408686688228.
The previous prime is 5113030032343. The next prime is 5113030032361. The reversal of 5113030032351 is 1532300303115.
5113030032351 is a `hidden beast` number, since 5 + 1 + 1 + 3 + 0 + 300 + 3 + 2 + 351 = 666.
It is not a de Polignac number, because 5113030032351 - 23 = 5113030032343 is a prime.
It is a super-2 number, since 2×51130300323512 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5113030032361) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 284057224011 + ... + 284057224028.
It is an arithmetic number, because the mean of its divisors is an integer number (1230914637420).
Almost surely, 25113030032351 is an apocalyptic number.
5113030032351 is a deficient number, since it is larger than the sum of its proper divisors (2272457792169).
5113030032351 is a wasteful number, since it uses less digits than its factorization.
5113030032351 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 568114448045 (or 568114448042 counting only the distinct ones).
The product of its (nonzero) digits is 4050, while the sum is 27.
Adding to 5113030032351 its reverse (1532300303115), we get a palindrome (6645330335466).
The spelling of 5113030032351 in words is "five trillion, one hundred thirteen billion, thirty million, thirty-two thousand, three hundred fifty-one".
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