Base | Representation |
---|---|
bin | 10011100000010100001111 |
3 | 100121202212012 |
4 | 103200110033 |
5 | 2302104403 |
6 | 301331435 |
7 | 61314002 |
oct | 23402417 |
9 | 10552765 |
10 | 5113103 |
11 | 2982606 |
12 | 1866b7b |
13 | 10a0408 |
14 | 971539 |
15 | 6aeed8 |
hex | 4e050f |
5113103 has 2 divisors, whose sum is σ = 5113104. Its totient is φ = 5113102.
The previous prime is 5113099. The next prime is 5113111. The reversal of 5113103 is 3013115.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5113103 - 22 = 5113099 is a prime.
It is a super-2 number, since 2×51131032 = 52287644577218, which contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5113123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2556551 + 2556552.
It is an arithmetic number, because the mean of its divisors is an integer number (2556552).
Almost surely, 25113103 is an apocalyptic number.
5113103 is a deficient number, since it is larger than the sum of its proper divisors (1).
5113103 is an equidigital number, since it uses as much as digits as its factorization.
5113103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 45, while the sum is 14.
The square root of 5113103 is about 2261.2171501207. The cubic root of 5113103 is about 172.2773490924.
Adding to 5113103 its reverse (3013115), we get a palindrome (8126218).
The spelling of 5113103 in words is "five million, one hundred thirteen thousand, one hundred three".
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