Base | Representation |
---|---|
bin | 100101001100111111001… |
… | …1000000100011110000111 |
3 | 200002210212220122200222101 |
4 | 1022121332120010132013 |
5 | 1132233143104234343 |
6 | 14512535021212531 |
7 | 1035261106061032 |
oct | 112317630043607 |
9 | 20083786580871 |
10 | 5113131321223 |
11 | 16a1515371652 |
12 | 6a6b61401147 |
13 | 2b1221234663 |
14 | 139696798019 |
15 | 8d00e69ce4d |
hex | 4a67e604787 |
5113131321223 has 2 divisors, whose sum is σ = 5113131321224. Its totient is φ = 5113131321222.
The previous prime is 5113131321211. The next prime is 5113131321239. The reversal of 5113131321223 is 3221231313115.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5113131321223 - 229 = 5112594450311 is a prime.
It is a super-2 number, since 2×51131313212232 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5113131321191 and 5113131321200.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5113131391223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2556565660611 + 2556565660612.
It is an arithmetic number, because the mean of its divisors is an integer number (2556565660612).
Almost surely, 25113131321223 is an apocalyptic number.
5113131321223 is a deficient number, since it is larger than the sum of its proper divisors (1).
5113131321223 is an equidigital number, since it uses as much as digits as its factorization.
5113131321223 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 3240, while the sum is 28.
Adding to 5113131321223 its reverse (3221231313115), we get a palindrome (8334362634338).
The spelling of 5113131321223 in words is "five trillion, one hundred thirteen billion, one hundred thirty-one million, three hundred twenty-one thousand, two hundred twenty-three".
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