Base | Representation |
---|---|
bin | 100101001100111111001… |
… | …1010101101001001000100 |
3 | 200002210212221221210200102 |
4 | 1022121332122231021010 |
5 | 1132233143243341400 |
6 | 14512535044103232 |
7 | 1035261114666200 |
oct | 112317632551104 |
9 | 20083787853612 |
10 | 5113132012100 |
11 | 16a15157a3722 |
12 | 6a6b61694b18 |
13 | 2b1221416c68 |
14 | 1396968d7b00 |
15 | 8d00e7879d5 |
hex | 4a67e6ad244 |
5113132012100 has 216 divisors, whose sum is σ = 13719475225512. Its totient is φ = 1643524915200.
The previous prime is 5113132012069. The next prime is 5113132012141. The reversal of 5113132012100 is 12102313115.
It can be written as a sum of positive squares in 12 ways, for example, as 341869412416 + 4771262599684 = 584696^2 + 2184322^2 .
It is a super-2 number, since 2×51131320121002 (a number of 26 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is an unprimeable number.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 21288680 + ... + 21527520.
It is an arithmetic number, because the mean of its divisors is an integer number (63516089007).
Almost surely, 25113132012100 is an apocalyptic number.
5113132012100 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 5113132012100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (6859737612756).
5113132012100 is an abundant number, since it is smaller than the sum of its proper divisors (8606343213412).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
5113132012100 is a wasteful number, since it uses less digits than its factorization.
5113132012100 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 239143 (or 239129 counting only the distinct ones).
The product of its (nonzero) digits is 180, while the sum is 20.
Adding to 5113132012100 its reverse (12102313115), we get a palindrome (5125234325215).
The spelling of 5113132012100 in words is "five trillion, one hundred thirteen billion, one hundred thirty-two million, twelve thousand, one hundred".
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