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511313303313103 is a prime number
BaseRepresentation
bin111010001000010010110011…
…1110100000001101011001111
32111001102002000020200200022011
41310100211213310001223033
51014004324121122004403
65011250031102402051
7212462111212440154
oct16420454764015317
92431362006620264
10511313303313103
11138a138328a0015
124941bb3a890327
1318c3c839aa6135
1490399a589622b
153e1a67462da6d
hex1d10967d01acf

511313303313103 has 2 divisors, whose sum is σ = 511313303313104. Its totient is φ = 511313303313102.

The previous prime is 511313303313091. The next prime is 511313303313143. The reversal of 511313303313103 is 301313303313115.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-511313303313103 is a prime.

It is a super-2 number, since 2×5113133033131032 (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (511313303313143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 255656651656551 + 255656651656552.

It is an arithmetic number, because the mean of its divisors is an integer number (255656651656552).

Almost surely, 2511313303313103 is an apocalyptic number.

511313303313103 is a deficient number, since it is larger than the sum of its proper divisors (1).

511313303313103 is an equidigital number, since it uses as much as digits as its factorization.

511313303313103 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10935, while the sum is 31.

Adding to 511313303313103 its reverse (301313303313115), we get a palindrome (812626606626218).

The spelling of 511313303313103 in words is "five hundred eleven trillion, three hundred thirteen billion, three hundred three million, three hundred thirteen thousand, one hundred three".