Base | Representation |
---|---|
bin | 101111100111101010… |
… | …100100001000100011 |
3 | 11212222102121221202200 |
4 | 233213222210020203 |
5 | 1314204110211303 |
6 | 35253413544243 |
7 | 3460040115054 |
oct | 574752441043 |
9 | 155872557680 |
10 | 51131335203 |
11 | 1a75933aa23 |
12 | 9aab945083 |
13 | 4a8b272340 |
14 | 2690aa872b |
15 | 14e3d6a3a3 |
hex | be7aa4223 |
51131335203 has 48 divisors (see below), whose sum is σ = 81297216000. Its totient is φ = 30770453952.
The previous prime is 51131335187. The next prime is 51131335231. The reversal of 51131335203 is 30253313115.
51131335203 is a `hidden beast` number, since 5 + 1 + 1 + 3 + 133 + 520 + 3 = 666.
51131335203 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 51131335203 - 24 = 51131335187 is a prime.
It is a super-2 number, since 2×511313352032 (a number of 22 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (51131335403) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 8239900 + ... + 8246102.
It is an arithmetic number, because the mean of its divisors is an integer number (1693692000).
Almost surely, 251131335203 is an apocalyptic number.
51131335203 is a deficient number, since it is larger than the sum of its proper divisors (30165880797).
51131335203 is a wasteful number, since it uses less digits than its factorization.
51131335203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7768 (or 7765 counting only the distinct ones).
The product of its (nonzero) digits is 4050, while the sum is 27.
Adding to 51131335203 its reverse (30253313115), we get a palindrome (81384648318).
The spelling of 51131335203 in words is "fifty-one billion, one hundred thirty-one million, three hundred thirty-five thousand, two hundred three".
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