Base | Representation |
---|---|
bin | 10111010000000111110011… |
… | …00001100000111100100111 |
3 | 20201001010021112202111221012 |
4 | 23220003321201200330213 |
5 | 23200214231103112241 |
6 | 300425250512212435 |
7 | 13525061444314622 |
oct | 1350037141407447 |
9 | 221033245674835 |
10 | 51131477004071 |
11 | 15323812857132 |
12 | 589975823a11b |
13 | 226b8a6893639 |
14 | c8aac3354db9 |
15 | 5da0a8c406eb |
hex | 2e80f9860f27 |
51131477004071 has 2 divisors, whose sum is σ = 51131477004072. Its totient is φ = 51131477004070.
The previous prime is 51131477004017. The next prime is 51131477004149. The reversal of 51131477004071 is 17040077413115.
Together with previous prime (51131477004017) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-51131477004071 is a prime.
It is a super-2 number, since 2×511314770040712 (a number of 28 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51131477004271) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25565738502035 + 25565738502036.
It is an arithmetic number, because the mean of its divisors is an integer number (25565738502036).
Almost surely, 251131477004071 is an apocalyptic number.
51131477004071 is a deficient number, since it is larger than the sum of its proper divisors (1).
51131477004071 is an equidigital number, since it uses as much as digits as its factorization.
51131477004071 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 82320, while the sum is 41.
The spelling of 51131477004071 in words is "fifty-one trillion, one hundred thirty-one billion, four hundred seventy-seven million, four thousand, seventy-one".
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