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51131477004071 is a prime number
BaseRepresentation
bin10111010000000111110011…
…00001100000111100100111
320201001010021112202111221012
423220003321201200330213
523200214231103112241
6300425250512212435
713525061444314622
oct1350037141407447
9221033245674835
1051131477004071
1115323812857132
12589975823a11b
13226b8a6893639
14c8aac3354db9
155da0a8c406eb
hex2e80f9860f27

51131477004071 has 2 divisors, whose sum is σ = 51131477004072. Its totient is φ = 51131477004070.

The previous prime is 51131477004017. The next prime is 51131477004149. The reversal of 51131477004071 is 17040077413115.

Together with previous prime (51131477004017) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-51131477004071 is a prime.

It is a super-2 number, since 2×511314770040712 (a number of 28 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (51131477004271) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25565738502035 + 25565738502036.

It is an arithmetic number, because the mean of its divisors is an integer number (25565738502036).

Almost surely, 251131477004071 is an apocalyptic number.

51131477004071 is a deficient number, since it is larger than the sum of its proper divisors (1).

51131477004071 is an equidigital number, since it uses as much as digits as its factorization.

51131477004071 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 82320, while the sum is 41.

The spelling of 51131477004071 in words is "fifty-one trillion, one hundred thirty-one billion, four hundred seventy-seven million, four thousand, seventy-one".