Base | Representation |
---|---|
bin | 100101001101000001110… |
… | …1111010100111101010001 |
3 | 200002211010011222022100012 |
4 | 1022122003233110331101 |
5 | 1132233334123213040 |
6 | 14512551554004305 |
7 | 1035263250652643 |
oct | 112320357247521 |
9 | 20084104868305 |
10 | 5113221304145 |
11 | 16a15611410a9 |
12 | 6a6b87576695 |
13 | 2b1236a7b8a6 |
14 | 1396a46dc893 |
15 | 8d017524865 |
hex | 4a683bd4f51 |
5113221304145 has 8 divisors (see below), whose sum is σ = 6347447136360. Its totient is φ = 3949522662400.
The previous prime is 5113221304091. The next prime is 5113221304151. The reversal of 5113221304145 is 5414031223115.
It can be written as a sum of positive squares in 4 ways, for example, as 1246331097664 + 3866890206481 = 1116392^2 + 1966441^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a de Polignac number, because none of the positive numbers 2k-5113221304145 is a prime.
It is a super-2 number, since 2×51132213041452 (a number of 26 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 17631797456 + ... + 17631797745.
It is an arithmetic number, because the mean of its divisors is an integer number (793430892045).
Almost surely, 25113221304145 is an apocalyptic number.
It is an amenable number.
5113221304145 is a deficient number, since it is larger than the sum of its proper divisors (1234225832215).
5113221304145 is a wasteful number, since it uses less digits than its factorization.
5113221304145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 35263595235.
The product of its (nonzero) digits is 14400, while the sum is 32.
The spelling of 5113221304145 in words is "five trillion, one hundred thirteen billion, two hundred twenty-one million, three hundred four thousand, one hundred forty-five".
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