Base | Representation |
---|---|
bin | 100101001101000010100… |
… | …1010101001110000010001 |
3 | 200002211011212000121020112 |
4 | 1022122011022221300101 |
5 | 1132233411240310213 |
6 | 14512554211051105 |
7 | 1035263661312464 |
oct | 112320512516021 |
9 | 20084155017215 |
10 | 5113245244433 |
11 | 16a1573702867 |
12 | 6a6b935a0a95 |
13 | 2b123ba11641 |
14 | 1396a79712db |
15 | 8d0196a2ea8 |
hex | 4a6852a9c11 |
5113245244433 has 2 divisors, whose sum is σ = 5113245244434. Its totient is φ = 5113245244432.
The previous prime is 5113245244397. The next prime is 5113245244463. The reversal of 5113245244433 is 3344425423115.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4313978848144 + 799266396289 = 2077012^2 + 894017^2 .
It is a cyclic number.
It is not a de Polignac number, because 5113245244433 - 228 = 5112976808977 is a prime.
It is a super-2 number, since 2×51132452444332 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5113245244463) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2556622622216 + 2556622622217.
It is an arithmetic number, because the mean of its divisors is an integer number (2556622622217).
Almost surely, 25113245244433 is an apocalyptic number.
It is an amenable number.
5113245244433 is a deficient number, since it is larger than the sum of its proper divisors (1).
5113245244433 is an equidigital number, since it uses as much as digits as its factorization.
5113245244433 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 691200, while the sum is 41.
The spelling of 5113245244433 in words is "five trillion, one hundred thirteen billion, two hundred forty-five million, two hundred forty-four thousand, four hundred thirty-three".
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