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5113255133117 is a prime number
BaseRepresentation
bin100101001101000010111…
…0000010111111110111101
3200002211012112121222222002
41022122011300113332331
51132233421303224432
614512555203032045
71035264141336455
oct112320560277675
920084175558862
105113255133117
1116a157924732a
126a6b9696b625
132b1240a94631
141396a8dc6d65
158d01a4a7e62
hex4a685c17fbd

5113255133117 has 2 divisors, whose sum is σ = 5113255133118. Its totient is φ = 5113255133116.

The previous prime is 5113255133099. The next prime is 5113255133141. The reversal of 5113255133117 is 7113315523115.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4982029346116 + 131225787001 = 2232046^2 + 362251^2 .

It is a cyclic number.

It is not a de Polignac number, because 5113255133117 - 216 = 5113255067581 is a prime.

It is a super-2 number, since 2×51132551331172 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5113255136117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2556627566558 + 2556627566559.

It is an arithmetic number, because the mean of its divisors is an integer number (2556627566559).

Almost surely, 25113255133117 is an apocalyptic number.

It is an amenable number.

5113255133117 is a deficient number, since it is larger than the sum of its proper divisors (1).

5113255133117 is an equidigital number, since it uses as much as digits as its factorization.

5113255133117 is an evil number, because the sum of its binary digits is even.

The product of its digits is 47250, while the sum is 38.

The spelling of 5113255133117 in words is "five trillion, one hundred thirteen billion, two hundred fifty-five million, one hundred thirty-three thousand, one hundred seventeen".