Base | Representation |
---|---|
bin | 101111100111110001… |
… | …010000000000001001 |
3 | 11212222112220222210221 |
4 | 233213301100000021 |
5 | 1314210032302003 |
6 | 35253515310041 |
7 | 3460061034406 |
oct | 574761200011 |
9 | 155875828727 |
10 | 51133087753 |
11 | 1a75a327710 |
12 | 9ab044b321 |
13 | 4a8b736c57 |
14 | 26910032ad |
15 | 14e40b47bd |
hex | be7c50009 |
51133087753 has 4 divisors (see below), whose sum is σ = 55781550288. Its totient is φ = 46484625220.
The previous prime is 51133087751. The next prime is 51133087763. The reversal of 51133087753 is 35778033115.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 51133087753 - 21 = 51133087751 is a prime.
It is a super-2 number, since 2×511330877532 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (51133087751) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2324231251 + ... + 2324231272.
It is an arithmetic number, because the mean of its divisors is an integer number (13945387572).
Almost surely, 251133087753 is an apocalyptic number.
It is an amenable number.
51133087753 is a deficient number, since it is larger than the sum of its proper divisors (4648462535).
51133087753 is a wasteful number, since it uses less digits than its factorization.
51133087753 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4648462534.
The product of its (nonzero) digits is 264600, while the sum is 43.
The spelling of 51133087753 in words is "fifty-one billion, one hundred thirty-three million, eighty-seven thousand, seven hundred fifty-three".
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