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51133305451 = 1012207229393
BaseRepresentation
bin101111100111110010…
…000101001001101011
311212222120100001102211
4233213302011021223
51314210111233301
635253524105551
73460062632164
oct574762051153
9155876301384
1051133305451
111a75a466228
129ab05352b7
134a8b7b2077
14269105c76b
1514e4109051
hexbe7c8526b

51133305451 has 8 divisors (see below), whose sum is σ = 51663199104. Its totient is φ = 50603875200.

The previous prime is 51133305407. The next prime is 51133305467. The reversal of 51133305451 is 15450333115.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 51133305451 - 227 = 50999087723 is a prime.

It is a super-2 number, since 2×511333054512 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (51133305401) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 108211 + ... + 337603.

It is an arithmetic number, because the mean of its divisors is an integer number (6457899888).

Almost surely, 251133305451 is an apocalyptic number.

51133305451 is a deficient number, since it is larger than the sum of its proper divisors (529893653).

51133305451 is a wasteful number, since it uses less digits than its factorization.

51133305451 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 231701.

The product of its (nonzero) digits is 13500, while the sum is 31.

Adding to 51133305451 its reverse (15450333115), we get a palindrome (66583638566).

The spelling of 51133305451 in words is "fifty-one billion, one hundred thirty-three million, three hundred five thousand, four hundred fifty-one".

Divisors: 1 101 2207 222907 229393 23168693 506270351 51133305451