Base | Representation |
---|---|
bin | 1110111000011100000… |
… | …10001011011000000101 |
3 | 1210212211220221122012001 |
4 | 13130032002023120011 |
5 | 31334204124411013 |
6 | 1030523233025301 |
7 | 51641253022150 |
oct | 7341602133005 |
9 | 1725756848161 |
10 | 511336560133 |
11 | 187947180963 |
12 | 831256b5231 |
13 | 392aca04119 |
14 | 1aa6aaa2c97 |
15 | d47b003ddd |
hex | 770e08b605 |
511336560133 has 16 divisors (see below), whose sum is σ = 604611204480. Its totient is φ = 423122325696.
The previous prime is 511336560121. The next prime is 511336560139. The reversal of 511336560133 is 331065633115.
It is a de Polignac number, because none of the positive numbers 2k-511336560133 is a prime.
It is a super-2 number, since 2×5113365601332 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 511336560092 and 511336560101.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (511336560139) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1519210 + ... + 1825012.
It is an arithmetic number, because the mean of its divisors is an integer number (37788200280).
Almost surely, 2511336560133 is an apocalyptic number.
It is an amenable number.
511336560133 is a deficient number, since it is larger than the sum of its proper divisors (93274644347).
511336560133 is a wasteful number, since it uses less digits than its factorization.
511336560133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 314076.
The product of its (nonzero) digits is 72900, while the sum is 37.
The spelling of 511336560133 in words is "five hundred eleven billion, three hundred thirty-six million, five hundred sixty thousand, one hundred thirty-three".
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