Base | Representation |
---|---|
bin | 111010001000011111001111… |
… | …1110110101010001111001101 |
3 | 2111001111121221201022012020021 |
4 | 1310100332133312222033031 |
5 | 1014010243321403101110 |
6 | 5011310205331022141 |
7 | 212464045133030506 |
oct | 16420763766521715 |
9 | 2431447851265207 |
10 | 511340013331405 |
11 | 138a24099a12105 |
12 | 49425153a3a951 |
13 | 18c42205685bab |
14 | 903adbadb1bad |
15 | 3e1b1d94d32da |
hex | 1d10f9fdaa3cd |
511340013331405 has 16 divisors (see below), whose sum is σ = 613685652547968. Its totient is φ = 409020256008000.
The previous prime is 511340013331393. The next prime is 511340013331493. The reversal of 511340013331405 is 504133310043115.
It is not a de Polignac number, because 511340013331405 - 25 = 511340013331373 is a prime.
It is a super-2 number, since 2×5113400133314052 (a number of 30 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1488051160 + ... + 1488394750.
It is an arithmetic number, because the mean of its divisors is an integer number (38355353284248).
Almost surely, 2511340013331405 is an apocalyptic number.
It is an amenable number.
511340013331405 is a deficient number, since it is larger than the sum of its proper divisors (102345639216563).
511340013331405 is a wasteful number, since it uses less digits than its factorization.
511340013331405 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 380388.
The product of its (nonzero) digits is 32400, while the sum is 34.
The spelling of 511340013331405 in words is "five hundred eleven trillion, three hundred forty billion, thirteen million, three hundred thirty-one thousand, four hundred five".
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