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5113403544111 = 37865321670729
BaseRepresentation
bin100101001101000111010…
…0110100001001000101111
3200002211120212220001120120
41022122032212201020233
51132234222301402421
614513022024020023
71035300622660542
oct112321646411057
920084525801516
105113403544111
1116a1644aa3745
126a7018601613
132b12657581a5
141396c09ba859
158d0285218c6
hex4a68e9a122f

5113403544111 has 8 divisors (see below), whose sum is σ = 6817958389680. Its totient is φ = 3408892197312.

The previous prime is 5113403544091. The next prime is 5113403544127. The reversal of 5113403544111 is 1114453043115.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 5113403544111 - 229 = 5112866673199 is a prime.

It is a super-2 number, since 2×51134035441112 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5113403542111) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10599406 + ... + 11071323.

It is an arithmetic number, because the mean of its divisors is an integer number (852244798710).

Almost surely, 25113403544111 is an apocalyptic number.

5113403544111 is a deficient number, since it is larger than the sum of its proper divisors (1704554845569).

5113403544111 is a wasteful number, since it uses less digits than its factorization.

5113403544111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 21749385.

The product of its (nonzero) digits is 14400, while the sum is 33.

Adding to 5113403544111 its reverse (1114453043115), we get a palindrome (6227856587226).

The spelling of 5113403544111 in words is "five trillion, one hundred thirteen billion, four hundred three million, five hundred forty-four thousand, one hundred eleven".

Divisors: 1 3 78653 235959 21670729 65012187 1704467848037 5113403544111