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51134043115 = 510226808623
BaseRepresentation
bin101111100111110100…
…111001001111101011
311212222121201112022201
4233213310321033223
51314210303334430
635253552001031
73460102123621
oct574764711753
9155877645281
1051134043115
111a75a91a471
129ab0830177
134a8b9aca5c
1426911b1511
1514e42028ca
hexbe7d393eb

51134043115 has 4 divisors (see below), whose sum is σ = 61360851744. Its totient is φ = 40907234488.

The previous prime is 51134043089. The next prime is 51134043127.

51134043115 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 51134043115 - 223 = 51125654507 is a prime.

It is a super-2 number, since 2×511340431152 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5113404307 + ... + 5113404316.

It is an arithmetic number, because the mean of its divisors is an integer number (15340212936).

Almost surely, 251134043115 is an apocalyptic number.

51134043115 is a deficient number, since it is larger than the sum of its proper divisors (10226808629).

51134043115 is a wasteful number, since it uses less digits than its factorization.

51134043115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10226808628.

The product of its (nonzero) digits is 3600, while the sum is 28.

It can be divided in two parts, 511340 and 43115, that added together give a palindrome (554455).

The spelling of 51134043115 in words is "fifty-one billion, one hundred thirty-four million, forty-three thousand, one hundred fifteen".

Divisors: 1 5 10226808623 51134043115