Base | Representation |
---|---|
bin | 10111010000001100110010… |
… | …00011100111100100011011 |
3 | 20201001101012002002200111221 |
4 | 23220012121003213210123 |
5 | 23200240221300141220 |
6 | 300430412243232511 |
7 | 13525214664325345 |
oct | 1350063103474433 |
9 | 221041162080457 |
10 | 51134153521435 |
11 | 15324966664256 |
12 | 589a184678737 |
13 | 226bc1224771a |
14 | c8ac989d4295 |
15 | 5da1b3bd79aa |
hex | 2e81990e791b |
51134153521435 has 32 divisors (see below), whose sum is σ = 61815583589760. Its totient is φ = 40605424616448.
The previous prime is 51134153521393. The next prime is 51134153521439. The reversal of 51134153521435 is 53412535143115.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 51134153521435 - 217 = 51134153390363 is a prime.
It is a super-3 number, since 3×511341535214353 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 51134153521391 and 51134153521400.
It is not an unprimeable number, because it can be changed into a prime (51134153521439) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3455703457 + ... + 3455718253.
It is an arithmetic number, because the mean of its divisors is an integer number (1931736987180).
Almost surely, 251134153521435 is an apocalyptic number.
51134153521435 is a deficient number, since it is larger than the sum of its proper divisors (10681430068325).
51134153521435 is a wasteful number, since it uses less digits than its factorization.
51134153521435 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24327.
The product of its digits is 540000, while the sum is 43.
The spelling of 51134153521435 in words is "fifty-one trillion, one hundred thirty-four billion, one hundred fifty-three million, five hundred twenty-one thousand, four hundred thirty-five".
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