Base | Representation |
---|---|
bin | 1110111000011100101… |
… | …11000000011001111111 |
3 | 1210212212022020001000121 |
4 | 13130032113000121333 |
5 | 31334212024121343 |
6 | 1030523550035411 |
7 | 51641350312606 |
oct | 7341627003177 |
9 | 1725768201017 |
10 | 511342020223 |
11 | 18794a270131 |
12 | 831274a8b67 |
13 | 392b0b96448 |
14 | 1aa6b6c4a3d |
15 | d47b731aed |
hex | 770e5c067f |
511342020223 has 2 divisors, whose sum is σ = 511342020224. Its totient is φ = 511342020222.
The previous prime is 511342020169. The next prime is 511342020247. The reversal of 511342020223 is 322020243115.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 511342020223 - 229 = 510805149311 is a prime.
It is a super-2 number, since 2×5113420202232 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (511342020323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 255671010111 + 255671010112.
It is an arithmetic number, because the mean of its divisors is an integer number (255671010112).
Almost surely, 2511342020223 is an apocalyptic number.
511342020223 is a deficient number, since it is larger than the sum of its proper divisors (1).
511342020223 is an equidigital number, since it uses as much as digits as its factorization.
511342020223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 511342020223 its reverse (322020243115), we get a palindrome (833362263338).
The spelling of 511342020223 in words is "five hundred eleven billion, three hundred forty-two million, twenty thousand, two hundred twenty-three".
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