Base | Representation |
---|---|
bin | 100101001101001010111… |
… | …0111111001010111100001 |
3 | 200002211220101110002220201 |
4 | 1022122111313321113201 |
5 | 1132240000014242241 |
6 | 14513042102505201 |
7 | 1035303633634612 |
oct | 112322567712741 |
9 | 20084811402821 |
10 | 5113525540321 |
11 | 16a16a7949260 |
12 | 6a7051435201 |
13 | 2b1284b008b3 |
14 | 1396d2c95c09 |
15 | 8d0340bd931 |
hex | 4a695df95e1 |
5113525540321 has 8 divisors (see below), whose sum is σ = 5578417063584. Its totient is φ = 4648638277920.
The previous prime is 5113525540313. The next prime is 5113525540351. The reversal of 5113525540321 is 1230455253115.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5113525540321 - 23 = 5113525540313 is a prime.
It is a super-2 number, since 2×51135255403212 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5113525540351) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1772910 + ... + 3656536.
It is an arithmetic number, because the mean of its divisors is an integer number (697302132948).
Almost surely, 25113525540321 is an apocalyptic number.
It is an amenable number.
5113525540321 is a deficient number, since it is larger than the sum of its proper divisors (464891523263).
5113525540321 is a wasteful number, since it uses less digits than its factorization.
5113525540321 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2130431.
The product of its (nonzero) digits is 90000, while the sum is 37.
The spelling of 5113525540321 in words is "five trillion, one hundred thirteen billion, five hundred twenty-five million, five hundred forty thousand, three hundred twenty-one".
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