51135255433 has 4 divisors (see below), whose sum is σ = 51143731780. Its totient is φ = 51126779088.

The previous prime is 51135255397. The next prime is 51135255461. The reversal of 51135255433 is 33455253115.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 33455253115 = 5 ⋅6691050623.

It can be written as a sum of positive squares in 2 ways, for example, as 36150557689 + 14984697744 = 190133^2 + 122412^2 .

It is a cyclic number.

It is not a de Polignac number, because 51135255433 - 2²⁹ = 50598384521 is a prime.

It is a super-4 number, since 4×51135255433⁴ (a number of 44 digits) contains 4444 as substring. Note that it is a super-d number also for d = 3, 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 51135255392 and 51135255401.

It is not an unprimeable number, because it can be changed into a prime (51135255133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4229118 + ... + 4241191.

It is an arithmetic number, because the mean of its divisors is an integer number (12785932945).

Almost surely, 2^51135255433 is an apocalyptic number.

It is an amenable number.

51135255433 is a deficient number, since it is larger than the sum of its proper divisors (8476347).

51135255433 is an equidigital number, since it uses as much as digits as its factorization.

51135255433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8476346.

The product of its digits is 135000, while the sum is 37.

The spelling of 51135255433 in words is "fifty-one billion, one hundred thirty-five million, two hundred fifty-five thousand, four hundred thirty-three".