Base | Representation |
---|---|
bin | 100101001101001101100… |
… | …1101111011011011011011 |
3 | 200002212010122011101122001 |
4 | 1022122123031323123123 |
5 | 1132240140442431021 |
6 | 14513055024341431 |
7 | 1035306103021141 |
oct | 112323315733333 |
9 | 20085118141561 |
10 | 5113615202011 |
11 | 16a1743519428 |
12 | 6a7077474877 |
13 | 2b129a564854 |
14 | 139700b55591 |
15 | 8d03bdd0091 |
hex | 4a69b37b6db |
5113615202011 has 4 divisors (see below), whose sum is σ = 5126367360024. Its totient is φ = 5100863044000.
The previous prime is 5113615201991. The next prime is 5113615202147. The reversal of 5113615202011 is 1102025163115.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5113615202011 - 211 = 5113615199963 is a prime.
It is a super-2 number, since 2×51136152020112 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5113615202611) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6376078405 + ... + 6376079206.
It is an arithmetic number, because the mean of its divisors is an integer number (1281591840006).
Almost surely, 25113615202011 is an apocalyptic number.
5113615202011 is a deficient number, since it is larger than the sum of its proper divisors (12752158013).
5113615202011 is a wasteful number, since it uses less digits than its factorization.
5113615202011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12752158012.
The product of its (nonzero) digits is 1800, while the sum is 28.
The spelling of 5113615202011 in words is "five trillion, one hundred thirteen billion, six hundred fifteen million, two hundred two thousand, eleven".
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