Base | Representation |
---|---|
bin | 1001100001101000… |
… | …00101110110101101 |
3 | 111012101202111221201 |
4 | 10300310011312231 |
5 | 40433131213013 |
6 | 2203241125501 |
7 | 240504452245 |
oct | 46064056655 |
9 | 14171674851 |
10 | 5113929133 |
11 | 2194752715 |
12 | ba8789891 |
13 | 63663b491 |
14 | 36727ab25 |
15 | 1ede5d3dd |
hex | 130d05dad |
5113929133 has 2 divisors, whose sum is σ = 5113929134. Its totient is φ = 5113929132.
The previous prime is 5113929113. The next prime is 5113929157. The reversal of 5113929133 is 3319293115.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5024399689 + 89529444 = 70883^2 + 9462^2 .
It is a cyclic number.
It is not a de Polignac number, because 5113929133 - 25 = 5113929101 is a prime.
It is a super-2 number, since 2×51139291332 = 52304542354692263378, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5113929092 and 5113929101.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5113929113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2556964566 + 2556964567.
It is an arithmetic number, because the mean of its divisors is an integer number (2556964567).
Almost surely, 25113929133 is an apocalyptic number.
It is an amenable number.
5113929133 is a deficient number, since it is larger than the sum of its proper divisors (1).
5113929133 is an equidigital number, since it uses as much as digits as its factorization.
5113929133 is an evil number, because the sum of its binary digits is even.
The product of its digits is 21870, while the sum is 37.
The square root of 5113929133 is about 71511.7412247807. The cubic root of 5113929133 is about 1722.8662697697.
The spelling of 5113929133 in words is "five billion, one hundred thirteen million, nine hundred twenty-nine thousand, one hundred thirty-three".
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