Base | Representation |
---|---|
bin | 101111101000001100… |
… | …011011101100100111 |
3 | 11220000001100000120002 |
4 | 233220030123230213 |
5 | 1314213343313133 |
6 | 35254332131515 |
7 | 3460205433326 |
oct | 575014335447 |
9 | 156001300502 |
10 | 51140213543 |
11 | 1a7633543a1 |
12 | 9ab2906b9b |
13 | 4a900604b3 |
14 | 2691d3a0bd |
15 | 14e4a20ce8 |
hex | be831bb27 |
51140213543 has 4 divisors (see below), whose sum is σ = 51425913240. Its totient is φ = 50854513848.
The previous prime is 51140213507. The next prime is 51140213557. The reversal of 51140213543 is 34531204115.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 51140213543 - 212 = 51140209447 is a prime.
It is a super-2 number, since 2×511402135432 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51140213563) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 142849580 + ... + 142849937.
It is an arithmetic number, because the mean of its divisors is an integer number (12856478310).
Almost surely, 251140213543 is an apocalyptic number.
51140213543 is a deficient number, since it is larger than the sum of its proper divisors (285699697).
51140213543 is a wasteful number, since it uses less digits than its factorization.
51140213543 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 285699696.
The product of its (nonzero) digits is 7200, while the sum is 29.
Adding to 51140213543 its reverse (34531204115), we get a palindrome (85671417658).
The spelling of 51140213543 in words is "fifty-one billion, one hundred forty million, two hundred thirteen thousand, five hundred forty-three".
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