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51140251273 is a prime number
BaseRepresentation
bin101111101000001100…
…100100111010001001
311220000001101221022111
4233220030210322021
51314213401020043
635254333022321
73460205651326
oct575014447211
9156001357274
1051140251273
111a76337a781
129ab29249a1
134a90074717
142691d49b4d
1514e4a2c09d
hexbe8324e89

51140251273 has 2 divisors, whose sum is σ = 51140251274. Its totient is φ = 51140251272.

The previous prime is 51140251247. The next prime is 51140251367. The reversal of 51140251273 is 37215204115.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 49172175504 + 1968075769 = 221748^2 + 44363^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-51140251273 is a prime.

It is not a weakly prime, because it can be changed into another prime (51140251223) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25570125636 + 25570125637.

It is an arithmetic number, because the mean of its divisors is an integer number (25570125637).

Almost surely, 251140251273 is an apocalyptic number.

It is an amenable number.

51140251273 is a deficient number, since it is larger than the sum of its proper divisors (1).

51140251273 is an equidigital number, since it uses as much as digits as its factorization.

51140251273 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8400, while the sum is 31.

Adding to 51140251273 its reverse (37215204115), we get a palindrome (88355455388).

The spelling of 51140251273 in words is "fifty-one billion, one hundred forty million, two hundred fifty-one thousand, two hundred seventy-three".