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51140415013 is a prime number
BaseRepresentation
bin101111101000001101…
…001100111000100101
311220000001201020220221
4233220031030320211
51314213421240023
635254340324341
73460210232602
oct575015147045
9156001636827
1051140415013
111a7634817a6
129ab29a36b1
134a901010cc
142691d8d6a9
1514e4a6085d
hexbe834ce25

51140415013 has 2 divisors, whose sum is σ = 51140415014. Its totient is φ = 51140415012.

The previous prime is 51140414993. The next prime is 51140415047. The reversal of 51140415013 is 31051404115.

51140415013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 42297269569 + 8843145444 = 205663^2 + 94038^2 .

It is a cyclic number.

It is not a de Polignac number, because 51140415013 - 217 = 51140283941 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (51140455013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25570207506 + 25570207507.

It is an arithmetic number, because the mean of its divisors is an integer number (25570207507).

Almost surely, 251140415013 is an apocalyptic number.

It is an amenable number.

51140415013 is a deficient number, since it is larger than the sum of its proper divisors (1).

51140415013 is an equidigital number, since it uses as much as digits as its factorization.

51140415013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1200, while the sum is 25.

Adding to 51140415013 its reverse (31051404115), we get a palindrome (82191819128).

The spelling of 51140415013 in words is "fifty-one billion, one hundred forty million, four hundred fifteen thousand, thirteen".