Search a number
-
+
5114042531404 = 221278510632851
BaseRepresentation
bin100101001101011010010…
…1100000011111001001100
3200002220020102020222100121
41022122310230003321030
51132242024342001104
614513205251434324
71035322512166342
oct112326454037114
920086212228317
105114042531404
1116a1942760314
126a71765b59a4
132b1337c54691
141397417d1992
158d064691254
hex4a6b4b03e4c

5114042531404 has 6 divisors (see below), whose sum is σ = 8949574429964. Its totient is φ = 2557021265700.

The previous prime is 5114042531399. The next prime is 5114042531413. The reversal of 5114042531404 is 4041352404115.

It is a happy number.

It is a super-2 number, since 2×51140425314042 (a number of 26 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 5114042531404.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 639255316422 + ... + 639255316429.

Almost surely, 25114042531404 is an apocalyptic number.

It is an amenable number.

5114042531404 is a deficient number, since it is larger than the sum of its proper divisors (3835531898560).

5114042531404 is a wasteful number, since it uses less digits than its factorization.

5114042531404 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1278510632855 (or 1278510632853 counting only the distinct ones).

The product of its (nonzero) digits is 38400, while the sum is 34.

Adding to 5114042531404 its reverse (4041352404115), we get a palindrome (9155394935519).

The spelling of 5114042531404 in words is "five trillion, one hundred fourteen billion, forty-two million, five hundred thirty-one thousand, four hundred four".

Divisors: 1 2 4 1278510632851 2557021265702 5114042531404