Base | Representation |
---|---|
bin | 101111101000001101… |
… | …100111100101010101 |
3 | 11220000001220210221022 |
4 | 233220031213211111 |
5 | 1314213433234443 |
6 | 35254342530525 |
7 | 3460211166461 |
oct | 575015474525 |
9 | 156001823838 |
10 | 51140524373 |
11 | 1a763546984 |
12 | 9ab2a36a45 |
13 | 4a9013bb13 |
14 | 2691dbb4a1 |
15 | 14e4a82e68 |
hex | be8367955 |
51140524373 has 2 divisors, whose sum is σ = 51140524374. Its totient is φ = 51140524372.
The previous prime is 51140524349. The next prime is 51140524429. The reversal of 51140524373 is 37342504115.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 29284450129 + 21856074244 = 171127^2 + 147838^2 .
It is a cyclic number.
It is not a de Polignac number, because 51140524373 - 28 = 51140524117 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51140524313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25570262186 + 25570262187.
It is an arithmetic number, because the mean of its divisors is an integer number (25570262187).
Almost surely, 251140524373 is an apocalyptic number.
It is an amenable number.
51140524373 is a deficient number, since it is larger than the sum of its proper divisors (1).
51140524373 is an equidigital number, since it uses as much as digits as its factorization.
51140524373 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 50400, while the sum is 35.
The spelling of 51140524373 in words is "fifty-one billion, one hundred forty million, five hundred twenty-four thousand, three hundred seventy-three".
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