Base | Representation |
---|---|
bin | 10111010000011000101100… |
… | …10101100101100111100011 |
3 | 20201001222200212212022110201 |
4 | 23220030112111211213203 |
5 | 23200341321342220311 |
6 | 300433351113410031 |
7 | 13525532340433240 |
oct | 1350142625454743 |
9 | 221058625768421 |
10 | 51140550351331 |
11 | 15327649495231 |
12 | 589b46aa09917 |
13 | 226c6c15b4b7c |
14 | c8b3043c05c7 |
15 | 5da43a5a99c1 |
hex | 2e83165659e3 |
51140550351331 has 4 divisors (see below), whose sum is σ = 58446343258672. Its totient is φ = 43834757443992.
The previous prime is 51140550351329. The next prime is 51140550351337. The reversal of 51140550351331 is 13315305504115.
51140550351331 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 51140550351331 - 21 = 51140550351329 is a prime.
It is a super-2 number, since 2×511405503513312 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (51140550351337) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3652896453660 + ... + 3652896453673.
It is an arithmetic number, because the mean of its divisors is an integer number (14611585814668).
Almost surely, 251140550351331 is an apocalyptic number.
51140550351331 is a deficient number, since it is larger than the sum of its proper divisors (7305792907341).
51140550351331 is an equidigital number, since it uses as much as digits as its factorization.
51140550351331 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7305792907340.
The product of its (nonzero) digits is 67500, while the sum is 37.
Adding to 51140550351331 its reverse (13315305504115), we get a palindrome (64455855855446).
The spelling of 51140550351331 in words is "fifty-one trillion, one hundred forty billion, five hundred fifty million, three hundred fifty-one thousand, three hundred thirty-one".
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