Base | Representation |
---|---|
bin | 10111010000011000101100… |
… | …11101001100001100001100 |
3 | 20201001222201000121120100120 |
4 | 23220030112131030030030 |
5 | 23200341322400004312 |
6 | 300433351224224540 |
7 | 13525532363403603 |
oct | 1350142635141414 |
9 | 221058630546316 |
10 | 51140552344332 |
11 | 1532764a626640 |
12 | 589b46b60b150 |
13 | 226c6c1b32069 |
14 | c8b30477ca3a |
15 | 5da43a85028c |
hex | 2e831674c30c |
51140552344332 has 48 divisors (see below), whose sum is σ = 130177084162944. Its totient is φ = 15497002224000.
The previous prime is 51140552344313. The next prime is 51140552344397. The reversal of 51140552344332 is 23344325504115.
It is a super-3 number, since 3×511405523443323 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 14099232 + ... + 17351352.
It is an arithmetic number, because the mean of its divisors is an integer number (2712022586728).
Almost surely, 251140552344332 is an apocalyptic number.
It is an amenable number.
51140552344332 is an abundant number, since it is smaller than the sum of its proper divisors (79036531818612).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
51140552344332 is a wasteful number, since it uses less digits than its factorization.
51140552344332 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3371270 (or 3371268 counting only the distinct ones).
The product of its (nonzero) digits is 864000, while the sum is 42.
Adding to 51140552344332 its reverse (23344325504115), we get a palindrome (74484877848447).
The spelling of 51140552344332 in words is "fifty-one trillion, one hundred forty billion, five hundred fifty-two million, three hundred forty-four thousand, three hundred thirty-two".
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