5114116114115 has 4 divisors (see below), whose sum is σ = 6136939336944. Its totient is φ = 4091292891288.

The previous prime is 5114116114103. The next prime is 5114116114117.

5114116114115 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5114116114115 - 2⁴ = 5114116114099 is a prime.

It is a super-3 number, since 3×5114116114115³ (a number of 39 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5114116114117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 511411611407 + ... + 511411611416.

It is an arithmetic number, because the mean of its divisors is an integer number (1534234834236).

Almost surely, 2^{5114116114115} is an apocalyptic number.

5114116114115 is a deficient number, since it is larger than the sum of its proper divisors (1022823222829).

5114116114115 is a wasteful number, since it uses less digits than its factorization.

5114116114115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1022823222828.

The product of its digits is 2400, while the sum is 32.

The spelling of 5114116114115 in words is "five trillion, one hundred fourteen billion, one hundred sixteen million, one hundred fourteen thousand, one hundred fifteen".