5114121253 has 4 divisors (see below), whose sum is σ = 5123471200. Its totient is φ = 5104771308.

The previous prime is 5114121211. The next prime is 5114121307. The reversal of 5114121253 is 3521214115.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5114121253 - 2²⁹ = 4577250341 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5114121053) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4674153 + ... + 4675246.

It is an arithmetic number, because the mean of its divisors is an integer number (1280867800).

Almost surely, 2^5114121253 is an apocalyptic number.

It is an amenable number.

5114121253 is a deficient number, since it is larger than the sum of its proper divisors (9349947).

5114121253 is an equidigital number, since it uses as much as digits as its factorization.

5114121253 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9349946.

The product of its digits is 1200, while the sum is 25.

The square root of 5114121253 is about 71513.0844880851. The cubic root of 5114121253 is about 1722.8878443694.

Adding to 5114121253 its reverse (3521214115), we get a palindrome (8635335368).

The spelling of 5114121253 in words is "five billion, one hundred fourteen million, one hundred twenty-one thousand, two hundred fifty-three".