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51141214451 = 215323753467
BaseRepresentation
bin101111101000010000…
…010000000011110011
311220000010012212112202
4233220100100003303
51314214122330301
635254405413415
73460220102405
oct575020200363
9156003185482
1051141214451
111a763978398
129ab310a26b
134a90320c52
14269211ab75
1514e4b6c66b
hexbe84100f3

51141214451 has 4 divisors (see below), whose sum is σ = 51164970072. Its totient is φ = 51117458832.

The previous prime is 51141214363. The next prime is 51141214469. The reversal of 51141214451 is 15441214115.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 15441214115 = 53088242823.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-51141214451 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (51141214151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11874581 + ... + 11878886.

It is an arithmetic number, because the mean of its divisors is an integer number (12791242518).

Almost surely, 251141214451 is an apocalyptic number.

51141214451 is a deficient number, since it is larger than the sum of its proper divisors (23755621).

51141214451 is a wasteful number, since it uses less digits than its factorization.

51141214451 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 23755620.

The product of its digits is 3200, while the sum is 29.

Adding to 51141214451 its reverse (15441214115), we get a palindrome (66582428566).

The spelling of 51141214451 in words is "fifty-one billion, one hundred forty-one million, two hundred fourteen thousand, four hundred fifty-one".

Divisors: 1 2153 23753467 51141214451