5114213437 has 4 divisors (see below), whose sum is σ = 5279188096. Its totient is φ = 4949238780.

The previous prime is 5114213359. The next prime is 5114213449. The reversal of 5114213437 is 7343124115.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-5114213437 is a prime.

It is a super-3 number, since 3×5114213437³ (a number of 30 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (31), and also a Moran number because the ratio is a prime number: 164974627 = 5114213437 / (5 + 1 + 1 + 4 + 2 + 1 + 3 + 4 + 3 + 7).

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 5114213399 and 5114213408.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5114219437) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 82487283 + ... + 82487344.

It is an arithmetic number, because the mean of its divisors is an integer number (1319797024).

Almost surely, 2^5114213437 is an apocalyptic number.

It is an amenable number.

5114213437 is a deficient number, since it is larger than the sum of its proper divisors (164974659).

5114213437 is a wasteful number, since it uses less digits than its factorization.

5114213437 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 164974658.

The product of its digits is 10080, while the sum is 31.

The square root of 5114213437 is about 71513.7290105893. The cubic root of 5114213437 is about 1722.8981962123.

The spelling of 5114213437 in words is "five billion, one hundred fourteen million, two hundred thirteen thousand, four hundred thirty-seven".