Base | Representation |
---|---|
bin | 101111101000010100… |
… | …011001110101001011 |
3 | 11220000012021011211021 |
4 | 233220110121311023 |
5 | 1314214412144201 |
6 | 35254445013311 |
7 | 3460232255230 |
oct | 575024316513 |
9 | 156005234737 |
10 | 51142303051 |
11 | 1a764551264 |
12 | 9ab3554237 |
13 | 4a906125a8 |
14 | 2692321787 |
15 | 14e4cd4ea1 |
hex | be8519d4b |
51142303051 has 4 divisors (see below), whose sum is σ = 58448346352. Its totient is φ = 43836259752.
The previous prime is 51142303033. The next prime is 51142303067. The reversal of 51142303051 is 15030324115.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-51142303051 is a prime.
It is a super-2 number, since 2×511423030512 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (51142303001) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3653021640 + ... + 3653021653.
It is an arithmetic number, because the mean of its divisors is an integer number (14612086588).
Almost surely, 251142303051 is an apocalyptic number.
51142303051 is a deficient number, since it is larger than the sum of its proper divisors (7306043301).
51142303051 is an equidigital number, since it uses as much as digits as its factorization.
51142303051 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7306043300.
The product of its (nonzero) digits is 1800, while the sum is 25.
Adding to 51142303051 its reverse (15030324115), we get a palindrome (66172627166).
The spelling of 51142303051 in words is "fifty-one billion, one hundred forty-two million, three hundred three thousand, fifty-one".
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