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51142303051 = 77306043293
BaseRepresentation
bin101111101000010100…
…011001110101001011
311220000012021011211021
4233220110121311023
51314214412144201
635254445013311
73460232255230
oct575024316513
9156005234737
1051142303051
111a764551264
129ab3554237
134a906125a8
142692321787
1514e4cd4ea1
hexbe8519d4b

51142303051 has 4 divisors (see below), whose sum is σ = 58448346352. Its totient is φ = 43836259752.

The previous prime is 51142303033. The next prime is 51142303067. The reversal of 51142303051 is 15030324115.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-51142303051 is a prime.

It is a super-2 number, since 2×511423030512 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (51142303001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3653021640 + ... + 3653021653.

It is an arithmetic number, because the mean of its divisors is an integer number (14612086588).

Almost surely, 251142303051 is an apocalyptic number.

51142303051 is a deficient number, since it is larger than the sum of its proper divisors (7306043301).

51142303051 is an equidigital number, since it uses as much as digits as its factorization.

51142303051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7306043300.

The product of its (nonzero) digits is 1800, while the sum is 25.

Adding to 51142303051 its reverse (15030324115), we get a palindrome (66172627166).

The spelling of 51142303051 in words is "fifty-one billion, one hundred forty-two million, three hundred three thousand, fifty-one".

Divisors: 1 7 7306043293 51142303051