Base | Representation |
---|---|
bin | 100101001101100011000… |
… | …0010001001101101011111 |
3 | 200002220222200211111100012 |
4 | 1022123012002021231133 |
5 | 1132243123341110241 |
6 | 14513254204553435 |
7 | 1035332644526465 |
oct | 112330602115537 |
9 | 20086880744305 |
10 | 5114333535071 |
11 | 16a1a81a4a712 |
12 | 6a7237b5287b |
13 | 2b13833226b7 |
14 | 13976c302835 |
15 | 8d07eec46eb |
hex | 4a6c6089b5f |
5114333535071 has 2 divisors, whose sum is σ = 5114333535072. Its totient is φ = 5114333535070.
The previous prime is 5114333535019. The next prime is 5114333535083. The reversal of 5114333535071 is 1705353334115.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5114333535071 - 218 = 5114333272927 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5114333535671) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2557166767535 + 2557166767536.
It is an arithmetic number, because the mean of its divisors is an integer number (2557166767536).
Almost surely, 25114333535071 is an apocalyptic number.
5114333535071 is a deficient number, since it is larger than the sum of its proper divisors (1).
5114333535071 is an equidigital number, since it uses as much as digits as its factorization.
5114333535071 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 283500, while the sum is 41.
Adding to 5114333535071 its reverse (1705353334115), we get a palindrome (6819686869186).
The spelling of 5114333535071 in words is "five trillion, one hundred fourteen billion, three hundred thirty-three million, five hundred thirty-five thousand, seventy-one".
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