51144601333 has 4 divisors (see below), whose sum is σ = 58450972960. Its totient is φ = 43838229708.

The previous prime is 51144601331. The next prime is 51144601357. The reversal of 51144601333 is 33310644115.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 51144601333 - 2¹ = 51144601331 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 51144601295 and 51144601304.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (51144601331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3653185803 + ... + 3653185816.

It is an arithmetic number, because the mean of its divisors is an integer number (14612743240).

Almost surely, 2^51144601333 is an apocalyptic number.

It is an amenable number.

51144601333 is a deficient number, since it is larger than the sum of its proper divisors (7306371627).

51144601333 is an equidigital number, since it uses as much as digits as its factorization.

51144601333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7306371626.

The product of its (nonzero) digits is 12960, while the sum is 31.

The spelling of 51144601333 in words is "fifty-one billion, one hundred forty-four million, six hundred one thousand, three hundred thirty-three".