Base | Representation |
---|---|
bin | 10111010000100111000001… |
… | …01111111011011010000011 |
3 | 20201002201112212120222121210 |
4 | 23220103200233323122003 |
5 | 23201003044223040001 |
6 | 300441102211421203 |
7 | 13526224045646436 |
oct | 1350234057733203 |
9 | 221081485528553 |
10 | 51148241221251 |
11 | 1532a935812679 |
12 | 58a0a565b4803 |
13 | 2270348a81585 |
14 | c8b8339b981d |
15 | 5da73a890dd6 |
hex | 2e84e0bfb683 |
51148241221251 has 32 divisors (see below), whose sum is σ = 71839854747648. Its totient is φ = 32306041396640.
The previous prime is 51148241221223. The next prime is 51148241221267. The reversal of 51148241221251 is 15212214284115.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 51148241221251 - 213 = 51148241213059 is a prime.
It is a super-2 number, since 2×511482412212512 (a number of 28 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (51148241121251) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 43802950 + ... + 44955476.
It is an arithmetic number, because the mean of its divisors is an integer number (2244995460864).
Almost surely, 251148241221251 is an apocalyptic number.
51148241221251 is a deficient number, since it is larger than the sum of its proper divisors (20691613526397).
51148241221251 is a wasteful number, since it uses less digits than its factorization.
51148241221251 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1158671.
The product of its digits is 51200, while the sum is 39.
The spelling of 51148241221251 in words is "fifty-one trillion, one hundred forty-eight billion, two hundred forty-one million, two hundred twenty-one thousand, two hundred fifty-one".
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