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51149339 is a prime number
BaseRepresentation
bin1100001100011…
…1101000011011
310120020122200222
43003013220123
5101043234324
65024150255
71160522303
oct303075033
9116218628
1051149339
112696628a
121516838b
13a79b5a7
146b16603
15475555e
hex30c7a1b

51149339 has 2 divisors, whose sum is σ = 51149340. Its totient is φ = 51149338.

The previous prime is 51149327. The next prime is 51149383. The reversal of 51149339 is 93394115.

51149339 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-51149339 is a prime.

It is a Chen prime.

It is equal to p3065858 and since 51149339 and 3065858 have the same sum of digits, it is a Honaker prime.

It is a junction number, because it is equal to n+sod(n) for n = 51149299 and 51149308.

It is not a weakly prime, because it can be changed into another prime (51149239) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25574669 + 25574670.

It is an arithmetic number, because the mean of its divisors is an integer number (25574670).

Almost surely, 251149339 is an apocalyptic number.

51149339 is a deficient number, since it is larger than the sum of its proper divisors (1).

51149339 is an equidigital number, since it uses as much as digits as its factorization.

51149339 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 14580, while the sum is 35.

The square root of 51149339 is about 7151.8766068774. The cubic root of 51149339 is about 371.2045935995.

The spelling of 51149339 in words is "fifty-one million, one hundred forty-nine thousand, three hundred thirty-nine".