51150130117 has 2 divisors, whose sum is σ = 51150130118. Its totient is φ = 51150130116.

The previous prime is 51150130037. The next prime is 51150130153. The reversal of 51150130117 is 71103105115.

51150130117 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 51142013316 + 8116801 = 226146^2 + 2849^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-51150130117 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 51150130091 and 51150130100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (51150130817) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25575065058 + 25575065059.

It is an arithmetic number, because the mean of its divisors is an integer number (25575065059).

Almost surely, 2^51150130117 is an apocalyptic number.

It is an amenable number.

51150130117 is a deficient number, since it is larger than the sum of its proper divisors (1).

51150130117 is an equidigital number, since it uses as much as digits as its factorization.

51150130117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 525, while the sum is 25.

The spelling of 51150130117 in words is "fifty-one billion, one hundred fifty million, one hundred thirty thousand, one hundred seventeen".