Base | Representation |
---|---|
bin | 100101001101111000111… |
… | …0110100100000111011111 |
3 | 200002222212221011111011222 |
4 | 1022123301312210013133 |
5 | 1132301130041220012 |
6 | 14513455150003555 |
7 | 1035360112350065 |
oct | 112336166440737 |
9 | 20088787144158 |
10 | 5115068695007 |
11 | 16a2319a24207 |
12 | 6a74021a65bb |
13 | 2b146c72258b |
14 | 1397dbbd0035 |
15 | 8d0c47de972 |
hex | 4a6f1da41df |
5115068695007 has 4 divisors (see below), whose sum is σ = 5115240009360. Its totient is φ = 5114897380656.
The previous prime is 5115068695003. The next prime is 5115068695019. The reversal of 5115068695007 is 7005968605115.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5115068695007 - 22 = 5115068695003 is a prime.
It is a super-2 number, since 2×51150686950072 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 5115068695007.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5115068695003) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 85612382 + ... + 85672107.
It is an arithmetic number, because the mean of its divisors is an integer number (1278810002340).
Almost surely, 25115068695007 is an apocalyptic number.
5115068695007 is a deficient number, since it is larger than the sum of its proper divisors (171314353).
5115068695007 is a wasteful number, since it uses less digits than its factorization.
5115068695007 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 171314352.
The product of its (nonzero) digits is 2268000, while the sum is 53.
The spelling of 5115068695007 in words is "five trillion, one hundred fifteen billion, sixty-eight million, six hundred ninety-five thousand, seven".
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