Base | Representation |
---|---|
bin | 10111010000101100010110… |
… | …11110011010010001101010 |
3 | 20201002222221111022002201101 |
4 | 23220112023132122101222 |
5 | 23201024431004024114 |
6 | 300442254331512014 |
7 | 13526355036130603 |
oct | 1350261336322152 |
9 | 221088844262641 |
10 | 51151105533034 |
11 | 153310756264a1 |
12 | 58a15158b860a |
13 | 22706b4308210 |
14 | c8ba26180daa |
15 | 5da857080d74 |
hex | 2e858b79a46a |
51151105533034 has 64 divisors (see below), whose sum is σ = 84223994400000. Its totient is φ = 23156833674240.
The previous prime is 51151105533007. The next prime is 51151105533043. The reversal of 51151105533034 is 43033550115115.
51151105533034 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 51151105532984 and 51151105533002.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2728195092 + ... + 2728213840.
It is an arithmetic number, because the mean of its divisors is an integer number (1315999912500).
Almost surely, 251151105533034 is an apocalyptic number.
51151105533034 is a deficient number, since it is larger than the sum of its proper divisors (33072888866966).
51151105533034 is a wasteful number, since it uses less digits than its factorization.
51151105533034 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 28495.
The product of its (nonzero) digits is 67500, while the sum is 37.
Adding to 51151105533034 its reverse (43033550115115), we get a palindrome (94184655648149).
The spelling of 51151105533034 in words is "fifty-one trillion, one hundred fifty-one billion, one hundred five million, five hundred thirty-three thousand, thirty-four".
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