51152444131 has 2 divisors, whose sum is σ = 51152444132. Its totient is φ = 51152444130.

The previous prime is 51152444129. The next prime is 51152444141. The reversal of 51152444131 is 13144425115.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 51152444131 - 2¹ = 51152444129 is a prime.

It is a super-2 number, since 2×51152444131² (a number of 22 digits) contains 22 as substring.

Together with 51152444129, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 51152444093 and 51152444102.

It is not a weakly prime, because it can be changed into another prime (51152444141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25576222065 + 25576222066.

It is an arithmetic number, because the mean of its divisors is an integer number (25576222066).

Almost surely, 2^51152444131 is an apocalyptic number.

51152444131 is a deficient number, since it is larger than the sum of its proper divisors (1).

51152444131 is an equidigital number, since it uses as much as digits as its factorization.

51152444131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 9600, while the sum is 31.

Adding to 51152444131 its reverse (13144425115), we get a palindrome (64296869246).

The spelling of 51152444131 in words is "fifty-one billion, one hundred fifty-two million, four hundred forty-four thousand, one hundred thirty-one".