5115313033 has 2 divisors, whose sum is σ = 5115313034. Its totient is φ = 5115313032.

The previous prime is 5115313001. The next prime is 5115313037. The reversal of 5115313033 is 3303135115.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2634974224 + 2480338809 = 51332^2 + 49803^2 .

It is a cyclic number.

It is not a de Polignac number, because 5115313033 - 2⁵ = 5115313001 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5115312989 and 5115313007.

It is not a weakly prime, because it can be changed into another prime (5115313037) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2557656516 + 2557656517.

It is an arithmetic number, because the mean of its divisors is an integer number (2557656517).

Almost surely, 2^5115313033 is an apocalyptic number.

It is an amenable number.

5115313033 is a deficient number, since it is larger than the sum of its proper divisors (1).

5115313033 is an equidigital number, since it uses as much as digits as its factorization.

5115313033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2025, while the sum is 25.

The square root of 5115313033 is about 71521.4166036999. The cubic root of 5115313033 is about 1723.0216662387.

Adding to 5115313033 its reverse (3303135115), we get a palindrome (8418448148).

The spelling of 5115313033 in words is "five billion, one hundred fifteen million, three hundred thirteen thousand, thirty-three".