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5115340050241 is a prime number
BaseRepresentation
bin100101001110000001000…
…0001101100111101000001
3200010000120211202202120211
41022130002001230331001
51132302204023101431
614513542122034121
71035366616004161
oct112340201547501
920100524682524
105115340050241
1116a2449113433
126a7479048941
132b14b3a011c5
14139825c685a1
158d0dd5412b1
hex4a70206cf41

5115340050241 has 2 divisors, whose sum is σ = 5115340050242. Its totient is φ = 5115340050240.

The previous prime is 5115340050221. The next prime is 5115340050269. The reversal of 5115340050241 is 1420500435115.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3543335640625 + 1572004409616 = 1882375^2 + 1253796^2 .

It is a cyclic number.

It is not a de Polignac number, because 5115340050241 - 25 = 5115340050209 is a prime.

It is not a weakly prime, because it can be changed into another prime (5115340050221) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2557670025120 + 2557670025121.

It is an arithmetic number, because the mean of its divisors is an integer number (2557670025121).

Almost surely, 25115340050241 is an apocalyptic number.

It is an amenable number.

5115340050241 is a deficient number, since it is larger than the sum of its proper divisors (1).

5115340050241 is an equidigital number, since it uses as much as digits as its factorization.

5115340050241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12000, while the sum is 31.

Adding to 5115340050241 its reverse (1420500435115), we get a palindrome (6535840485356).

The spelling of 5115340050241 in words is "five trillion, one hundred fifteen billion, three hundred forty million, fifty thousand, two hundred forty-one".