Search a number
-
+
51155153132341 is a prime number
BaseRepresentation
bin10111010000110011111001…
…01110110001101100110101
320201010101101120120110010211
423220121330232301230311
523201111223200213331
6300444204121545421
713526560245142636
oct1350317456615465
9221111346513124
1051155153132341
1115332862370795
1258a2265345271
132270baaa543ab
14c8bccb96588d
155da9e25a98b1
hex2e867cbb1b35

51155153132341 has 2 divisors, whose sum is σ = 51155153132342. Its totient is φ = 51155153132340.

The previous prime is 51155153132311. The next prime is 51155153132357. The reversal of 51155153132341 is 14323135155115.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 48938839096900 + 2216314035441 = 6995630^2 + 1488729^2 .

It is a cyclic number.

It is not a de Polignac number, because 51155153132341 - 225 = 51155119577909 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 51155153132294 and 51155153132303.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (51155153132311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25577576566170 + 25577576566171.

It is an arithmetic number, because the mean of its divisors is an integer number (25577576566171).

Almost surely, 251155153132341 is an apocalyptic number.

It is an amenable number.

51155153132341 is a deficient number, since it is larger than the sum of its proper divisors (1).

51155153132341 is an equidigital number, since it uses as much as digits as its factorization.

51155153132341 is an evil number, because the sum of its binary digits is even.

The product of its digits is 135000, while the sum is 40.

Adding to 51155153132341 its reverse (14323135155115), we get a palindrome (65478288287456).

The spelling of 51155153132341 in words is "fifty-one trillion, one hundred fifty-five billion, one hundred fifty-three million, one hundred thirty-two thousand, three hundred forty-one".