Base | Representation |
---|---|
bin | 101111101001000110… |
… | …111100000001011101 |
3 | 11220001010012012122011 |
4 | 233221012330001131 |
5 | 1314231310102201 |
6 | 35300040551221 |
7 | 3460453001032 |
oct | 575106740135 |
9 | 156033165564 |
10 | 51155550301 |
11 | 1a770a7a0a9 |
12 | 9ab7a82511 |
13 | 4a932a01bb |
14 | 2693dad389 |
15 | 14e6050151 |
hex | be91bc05d |
51155550301 has 2 divisors, whose sum is σ = 51155550302. Its totient is φ = 51155550300.
The previous prime is 51155550293. The next prime is 51155550307. The reversal of 51155550301 is 10305555115.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 51143370201 + 12180100 = 226149^2 + 3490^2 .
It is a cyclic number.
It is not a de Polignac number, because 51155550301 - 23 = 51155550293 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51155550307) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25577775150 + 25577775151.
It is an arithmetic number, because the mean of its divisors is an integer number (25577775151).
Almost surely, 251155550301 is an apocalyptic number.
It is an amenable number.
51155550301 is a deficient number, since it is larger than the sum of its proper divisors (1).
51155550301 is an equidigital number, since it uses as much as digits as its factorization.
51155550301 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9375, while the sum is 31.
The spelling of 51155550301 in words is "fifty-one billion, one hundred fifty-five million, five hundred fifty thousand, three hundred one".
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