Base | Representation |
---|---|
bin | 101111101001011101… |
… | …011000011000000001 |
3 | 11220001112021010000011 |
4 | 233221131120120001 |
5 | 1314234311333401 |
6 | 35300411024521 |
7 | 3460554003355 |
oct | 575135303001 |
9 | 156045233004 |
10 | 51161433601 |
11 | 1a774328333 |
12 | 9ab9a3b141 |
13 | 4a94580045 |
14 | 2694aa1465 |
15 | 14e6813451 |
hex | be9758601 |
51161433601 has 2 divisors, whose sum is σ = 51161433602. Its totient is φ = 51161433600.
The previous prime is 51161433461. The next prime is 51161433677. The reversal of 51161433601 is 10633416115.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 47750990400 + 3410443201 = 218520^2 + 58399^2 .
It is a cyclic number.
It is not a de Polignac number, because 51161433601 - 217 = 51161302529 is a prime.
It is not a weakly prime, because it can be changed into another prime (51161433691) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25580716800 + 25580716801.
It is an arithmetic number, because the mean of its divisors is an integer number (25580716801).
Almost surely, 251161433601 is an apocalyptic number.
It is an amenable number.
51161433601 is a deficient number, since it is larger than the sum of its proper divisors (1).
51161433601 is an equidigital number, since it uses as much as digits as its factorization.
51161433601 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6480, while the sum is 31.
Adding to 51161433601 its reverse (10633416115), we get a palindrome (61794849716).
The spelling of 51161433601 in words is "fifty-one billion, one hundred sixty-one million, four hundred thirty-three thousand, six hundred one".
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