Base | Representation |
---|---|
bin | 100101001110011001110… |
… | …0111100100110000000111 |
3 | 200010002201211100022202011 |
4 | 1022130303213210300013 |
5 | 1132310410021433303 |
6 | 14514200442555051 |
7 | 1035426340664443 |
oct | 112346347446007 |
9 | 20102654308664 |
10 | 5116172061703 |
11 | 16a2835828a0a |
12 | 6a766b808a87 |
13 | 2b15b71b1791 |
14 | 1398a4567823 |
15 | 8d13b5dd16d |
hex | 4a7339e4c07 |
5116172061703 has 4 divisors (see below), whose sum is σ = 5235152807368. Its totient is φ = 4997191316040.
The previous prime is 5116172061701. The next prime is 5116172061739. The reversal of 5116172061703 is 3071602716115.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5116172061703 - 21 = 5116172061701 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5116172061701) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 59490372768 + ... + 59490372853.
It is an arithmetic number, because the mean of its divisors is an integer number (1308788201842).
Almost surely, 25116172061703 is an apocalyptic number.
5116172061703 is a deficient number, since it is larger than the sum of its proper divisors (118980745665).
5116172061703 is a wasteful number, since it uses less digits than its factorization.
5116172061703 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 118980745664.
The product of its (nonzero) digits is 52920, while the sum is 40.
Adding to 5116172061703 its reverse (3071602716115), we get a palindrome (8187774777818).
The spelling of 5116172061703 in words is "five trillion, one hundred sixteen billion, one hundred seventy-two million, sixty-one thousand, seven hundred three".
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