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5117110020127 = 7731015717161
BaseRepresentation
bin100101001110110101110…
…0001100110100000011111
3200010012011012021112211001
41022131223201212200133
51132314320131121002
614514433510411131
71035461520336220
oct112355341464037
920105135245731
105117110020127
1116a3177226a66
126a7891960aa7
132b1706608671
14139952d65247
158d193b16a87
hex4a76b86681f

5117110020127 has 4 divisors (see below), whose sum is σ = 5848125737296. Its totient is φ = 4386094302960.

The previous prime is 5117110020103. The next prime is 5117110020149. The reversal of 5117110020127 is 7210200117115.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5117110020127 - 227 = 5116975802399 is a prime.

It is a super-2 number, since 2×51171100201272 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 5117110020095 and 5117110020104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5117110020157) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 365507858574 + ... + 365507858587.

It is an arithmetic number, because the mean of its divisors is an integer number (1462031434324).

Almost surely, 25117110020127 is an apocalyptic number.

5117110020127 is a deficient number, since it is larger than the sum of its proper divisors (731015717169).

5117110020127 is an equidigital number, since it uses as much as digits as its factorization.

5117110020127 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 731015717168.

The product of its (nonzero) digits is 980, while the sum is 28.

The spelling of 5117110020127 in words is "five trillion, one hundred seventeen billion, one hundred ten million, twenty thousand, one hundred twenty-seven".

Divisors: 1 7 731015717161 5117110020127