Base | Representation |
---|---|
bin | 100101001111010010110… |
… | …1010001111111111100101 |
3 | 200010021200011120020110101 |
4 | 1022132211222033333211 |
5 | 1132323314323200413 |
6 | 14515114351424101 |
7 | 1035524632544344 |
oct | 112364552177745 |
9 | 20107604506411 |
10 | 5118085365733 |
11 | 16a362784060a |
12 | 6a7b04525031 |
13 | 2b18306c2a42 |
14 | 139a066d5b5b |
15 | 8d1ee577edd |
hex | 4a7a5a8ffe5 |
5118085365733 has 2 divisors, whose sum is σ = 5118085365734. Its totient is φ = 5118085365732.
The previous prime is 5118085365667. The next prime is 5118085365761. The reversal of 5118085365733 is 3375635808115.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3545173076769 + 1572912288964 = 1882863^2 + 1254158^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5118085365733 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5118085305733) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2559042682866 + 2559042682867.
It is an arithmetic number, because the mean of its divisors is an integer number (2559042682867).
Almost surely, 25118085365733 is an apocalyptic number.
It is an amenable number.
5118085365733 is a deficient number, since it is larger than the sum of its proper divisors (1).
5118085365733 is an equidigital number, since it uses as much as digits as its factorization.
5118085365733 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9072000, while the sum is 55.
The spelling of 5118085365733 in words is "five trillion, one hundred eighteen billion, eighty-five million, three hundred sixty-five thousand, seven hundred thirty-three".
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